1.

A ray of light having intensity 0.5 (W)/(m^2) is incident perpendicular to the glass slab having refractive index 1.5. What will be intensity of partially refracted ray ?

Answer»

`0.04(W)/(m^2)`
`0.02(W)/(m^2)`
`2(W)/(m^2)`
`4(W)/(m^2)`

SOLUTION :INTENSITY of REFLECTED ray,
`I_r=I_0((n_2-n_1)^2)/((n_2+n_1)^2)`
`=0.5((1.5-1.0)^2)/(1.5+1.0)^2`
`=0.5xx(0.25)/(6.25)`
`THEREFORE I_r=0.02(W)/(m^2)`


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