1.

A ray of light incident at an angle theta on a refracting face of a prism emerges from the other face normally. If the angle of prism is 5^(@) and the prism is made of a material of refractive index 1.5, the angle of incidence is

Answer»

`7.5^(@)`
`5^(@)`
`15^(@)`
`2.5^(@)`

SOLUTION :Here `angleA=5^(@) and n = 1.5`. As the ray passes through the SECOND face of PRISM normally, hence `anglee=angler_(2)=0^(@)" and hence "angler_(1)=angleA=5^(@)`. If angle of incidence `i=theta`, then
`(sin theta)/(sin r_(1))=n or (sin theta)/(sin 5^(@))=1.5` As angle are small hence, we have
`(theta)/(5^(@))=1.5 or theta=5xx1.5-7.5^(@)`.


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