1.

A ray of light is incident normally on one face of a triangular prism of refracting angle 30^(@) and refractive index 1.5 Find the deviaton of the ray produced.

Answer»

`18.6^(@)`
`12.2^(@)`
`8.4^(@)`
`6.3^(@)`

Solution :(a) For normal incidence,I = 0 and r = 0
Now r + r. = A
`0 + r. = 30^(@), r. = 30^(@)`
`THEREFORE mu = (sin I.)/(sinr.), therefore I. = 1.5 sin 30^(@)`
`therefore I. = 48.6^(@)`
Now I + I. = A + D
`D = (i+I.) - A = 18.6^(@)`


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