1.

A ray of light is incident on the surface of separation of a medium at an angle 45^(@) and is refracted in the medium at an angle 30^(@). What will be the speed of light in the medium?

Answer»

`1.96xx10^(8)ms^(-1)`
`2.12xx10^(8)ms^(-1)`
`3.18xx10^(8)ms^(-1)`
`3.33xx10^(8)ms^(-1)`

Solution :(B) `N=(sin i )/(sin r)=c/v`

Hence `v=( c sin r)/(sin i)=(3XX10^(8)xxsin30^(@))/(sin 45^(@))`
`=(3xx10^(8))/(sqrt(2))=2.12xx10^(8)ms^(-1)`


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