1.

A ray of light passes from a medium A having refractive index 1.6 to the medium B having refractive index 1.5. The value of critical angle of medium A is ....

Answer»

`sin^(-1)((16)/(15))`
`sin^(-1)(1/2)`
`sin^(-1)SQRT((16)/(15))`
`sin^(-1)((15)/(16))`

Solution :Refractive INDEX of medium A with RESPECT to medium B
`n_(AB)=(n_A)/(n_B)`
`SINC=(1)/(n_(AB))=(n_B)/(n_A)`
`THEREFORE C=sin^(-1)((n_B)/(n_A))`
`=sin^(-1)((1.5)/(1.6))=sin^(-1)((15)/(16))`


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