1.

A ray of light passes from glass (mu = 1.5) to water (mu = 1.33). The value of the critical angle of glass is ..........

Answer»

`SIN^(-1)(8/9)`
`sin^(-1)(sqrt(8/9))`
`sin^(-1)(1/2)`
`sin^(-1)(2/1)`

SOLUTION :Refractive index n =`(1)/(sinC)implies sin C =1/n`
`therefore C=sin^(-1)(1/n)` …...........(1)
Here light RAY enter from to WATER, so relative refractive index will be taken.`therefore n=(n_g)/(n_w)=(1.5)/(1.33)`
`therefore1/n=(1.33)/(1.5)=8/9`
From equation (1), `C=sin^(-1)(8/9)`


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