1.

A ray of light passes through an equilateral glass prism in such a manner that the angle of incidence is equal to the angle of emergence and each of these is equal to (3)/(4)th of the angle of prism. The refractive index of the prism material is

Answer»

`(3)/(2)`
`sqrt2`
`SQRT3`
`(sqrt3)/(2)`

Solution :Here `ANGLEA=60^(@) and anglei=anglee=(3)/(4) angleA=(3)/(4)+60^(@)=45^(@)`
`therefore" Angle of MINIMUM deviation "delta_(m)=(2xx45^(@))-60^(@)=30^(@)`
`therefore""n=(sin((A+delta_(m))/(2)))/(sin((A)/(2)))=(sin(60^(@)+30^(@))/(2))/(sin((60^(@))/(2)))=(sin45^(@))/(sin 30^(@))=(1//sqrt2)/(1//2)=sqrt2`


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