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A ray of light passes through an equilateral glass prism in such a way that the angle of incidence is equal to the angle of emergence and each of these angles is 3/4times the angle of the prism. Determine the angle of deviation and the refractive index of the glass prism. |
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Answer» SOLUTION :Here angle of prism A = 60°, angle of incidence i = angle of emergence = e and under this CONDITION angle of deviation is minimum: `therefore i=e = 3/4A = 3/4 xx 60^(@) = 45^(@)` and `I + e=A + DELTA`, hence `D_(m) =2i -A = 2 xx 45^(@) - 60^(@) = 30^(@)` `therefore` Refractive index of glass prism `n=(sin(A+D_(m))/2)/(sinA/2) =(sin(60^(@) + 30^(@))/2)/(sin 60^(@)/2) = (sin 45^(@))/(sin 30^(@)) =(1//sqrt(2))/(1//2) = sqrt(2)` |
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