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A ray of light passes through four transparent media with refractive indices mu_(1),mu_(2),mu_(3), and mu_(4) as shown in figure. The surfaces of all media are paralle. If the emerent ray CD is parallel to the incident ray AB, we must have |
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Answer» `mu_(1)=mu_(2)` `.^(1)mu_(2)=(sini)/(sinr_(1))=(mu_(2))/(mu_(1))`(i) Applying Snlle's law at Q, `.^(2)mu_(3)=(sinr_(1))/(sinr_(2))=(mu_(3))/(mu_(2))`(ii) Again, applying Snell's law at R, `.^(3)mu_(4)=(sinr_(1))/(sinr_(2))=(mu_(4))/(mu_(3))` (iii) Multiplying (i), (ii) and (iii) , we get `mu_(4)=mu_(1)` Correct option is (d). 
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