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A ray of light passesthrough a glass slab of thickness t and refractive index mu. If velocity of light in vacuum is c then how much time will the light take to emerge from the slab? |
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Answer» Solution :VELOCITY of light in glass, `V = ( c )/(MU)` `THEREFORE "To overcome the glass slab of thickness t, time taken by light "` `= (t)/(v) = (t)/((c)/(mu))= (mut)/(c)` |
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