1.

A ray of light passing through a glass prism of refracting angle of 60^@ undergoes a minimum deviation of 30^@. Calculate the RI of glass prism?

Answer»

SOLUTION :`MU=(SIN 1/2((A+D_m)))/(sinA/2)=(sin(60+30))/2/sin60/2=(SIN45^@/sin 30^@)=1/sqrt2xx2=sqrt2=1.414`


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