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A ray of light strikes a horizontal plane mirror at an angle of 45^(@). At what angle should a second plane mirror be placed in order that the reflected ray finally be refracted horizontally from the second mirror: |
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Answer» `22.5^(@)` with horizontal  From fig. `theta + theta + 45^(@) = 180^(@)` So `"" theta = 67.5^(@)` Also `"" angle PCM_(2) = 90^(@)` `angle DCM_(2) = 90^(@) - 90^(@) - 67.5^(@)` `=22.5^(@)` with horizontal. |
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