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A ray of light travelling in the direction `(1)/(2)``(hati,+sqrt3hatj)` is incident on a plane mirror. After reflection, it travels along the direction (1)/(2)` `(hati-sqrt3hatj)` . The angle of incidence isA. `30^(@)`B. `45^(@)`C. `60^(@)`D. `75^(@)`

Answer» Correct Answer - A
Here normal is along `hatj`
Angle between incident ray and normal
`"cos"theta = ((1)/(2) (hati + sqrt(3hatj)). Hatj)/((1)(1)) = (sqrt(3))/(2) implies theta = 30^(@)`


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