1.

A reactant (A) froms two products, Aoverset(k_(1))toB, Activation Energy E_(a_(1)) Aoverset(k_(2))toB, Activation Energy E_(a_(2)) If E_(a_(1))=2E_(a_(2)), then k_(1) and k_(2) are related as:

Answer»

`k_(2)=k_(1)e^((E_(a_(1)))/(RT))`
`k_(2)=k_(1)e^((E_(a_(2)))/(RT))`
`k_(1)=Ak_(2)e^((E_(a_(1)))/(RT))`
`k_(1)=2k_(2)e^((E_(a_(1)))/(RT))`

SOLUTION :`k_(1)=A_(1)e^(-E_(a_(1)))/(RT)`….(i)
`k_(2)=A_(2)e^(-E_(a_(2)))/(RT)`….(ii)
On dividing EQN(i) from eqn(ii)
`(k_(1))/(k_(2))=(A_(1))/(A_(2))(E_(a_(1))-E_(a_(2)))/(RT)`… (iii)
Given `E_(a_(1))=E_(a_(2))`
On substituting this value in eqn. (iii)
`K_(1)=K_(2)Atimese^(E_(a_(1)))/(RT)`


Discussion

No Comment Found

Related InterviewSolutions