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A reaction has a forward rate constant of `2.3xx10^6 s^(-1)` and an equilibrium constant of `4.0xx10^8` .What is the rate constant for the reverse reaction ?A. `1.1xx10^(-15) s^(-1)`B. `5.8xx10^(-3) s^(-1)`C. `1.7xx10^(2) s^(-1)`D. `9.2xx10^(14) s^(-1)` |
Answer» Correct Answer - D |
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