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A reaction is first order in A and second order in B. How the rate is affected (a) on increasing concentration of B three times and (b) on increasing concentration of both A and B twice ? |
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Answer» SOLUTION :Rateis given as rate `=K[A][B]^(2)` (a) If concentration of B is increaseed three times, NEW rate `=K[A][3B]^(2)` `9K[A][B]^(2)` Hence rate is increased by `9` times (b) If concentration of both A and B are doubled, `"new rate"=K[2A][2B]^(2)` `8K[A][B]^(2)` Hence rate is increased by `8` times |
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