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A reaction is first order in A and second order in B. (i) Write the differential rate equation. (ii) How is the rte affected on increasing the concentration of B three times? (iii) How is the rate affected when concentrations of both A and B are doubled? |
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Answer» Solution :(i) `(dx)/(DT)=k[A][B]^(2)." Let"[A]=a and [B]=b`. Thus, `(dx)/(dt)=k ab^(2)`. (ii) If [B] is tripled, RATE `=k a(3b)^(2)=9kab^(2)`. The rate increases 9 times. (iii) If both [A] and [B] are doubled, Rate `=k(2a)(2B)^(2)=8 k ab^(2)`. The rate increases 8 times. |
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