1.

A reaction is of first order in reactant A and of second order in reactant B. How is the rate of this reaction affected when (i) the concentration of B alone is increased to three times, (ii) the concentrations of A as well as B are doubled ?

Answer»

Solution :According to QUESTION the given reaction is rate EQUATION
`:.` Rate = `k[A]^(1)[B]^(2)`
(i) When concentration of B is tripled it means conc. Of B becomes 3 times
Rate `= k[A][3B]^(2)`
`:.` The rate of reaction becomes 9 times
(ii) When conc. of A and B both is DOUBLED, then conc. of A becomes 2A and that of B becomes 2B.
`:.` Rate `= k[2A][2B]^(2)`
`= 8k[A][B]^(2)`
Rate of the reaction becomes 8 times.


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