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A reaction is second order with respect to a reactant. How is the rate of reaction affected if the concentration of the reactant is (i) Doubled (ii) reduced to half ? |
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Answer» Solution :(i) ` r = K[A]^(2) rArr r = k[2A]^(2) rArr r4k[A]^(2)` Rate increases by four times. (ii) ` r = k[A]^(2)` `r = k[(A)/(2)]^(2) rArr = (1)/(4) k[A]^(2)`. Rate increases by four times. |
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