1.

A reaction is secondorder with respect to a reactant . How is the rate of reaction affected if the concentration of the reactant is : (i) doubled (ii) reduced to half.

Answer»

Solution :(i) Reaction is SECOND ORDER with respect to the reactant
`:. "Rate" = K [ A] ^2 = ka ^2`
When [A]=2a
Rate = `k (2a)^2=4 ka ^2` = 4 times
Therefore , when concentration of the reactant is doubled the rate will become 4 times
(ii) when `[A]= 1/2 a`
Rate `=k(1/2a)^2=1/4ka^2=1/4k`
Therefore , rate will be reduced to one - fourthe the initial rate.


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