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A reaction P to Q is completed 25% in 25 min, 50% completed in 25 min if [P] is halved, 25% completed in 50 min if [P] is doubled. The order of reaction is

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Solution :By hit and trial method, if reaction is of zero order,
`K = (1)/(t){[A]_(0)-[A]}`
Case I. `k = (1)/(25) XX (25)/(100) = 10^(-2)`
Case II. `k = (1)/(25) xx (1)/(2) {[A]_(0)-[A]}` (as[P] is HALVED)
`= (1)/(25) xx (1)/(2) xx (50)/(100) = 10^(-2)`
Case III. `k = (1)/(50) xx 2{[A]_(0)-[A]}`
`""` (as [P] is doubled )
` = (1)/(50)k xx 2 xx (25)/(100) = 10^(-2)`
As k comes out to be constant, hence the given reaction is of zero order.


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