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A reaction takes place in two steps, 1. NO(g) + Cl2(g) NOCl2(g) 2. NOCl2(g) + NO(g) → 2NOCl(g) a. Write the overall reaction. b. Identify reaction intermediate. c. What is the molecularity of each step? |
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Answer» Given : (1) NO(g) + Cl2(g) → NOCl2(g) (2) NOCl2(g) + NO(g) → 2NOCl(g) (a) Overall reaction is obtained by adding both the reactions 2NO(g) + Cl2(g) → 2NOCl2(g) (b) The reaction intermediate is NOCl2, since it is formed in first step and consumed in the second step. (c) Since the first step is a slow and rate determining step, the molecularity is two. Since the second step is a fast step its molecularity is not considered. |
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