1.

A reaction takes place in two steps, 1. NO(g) + Cl2(g) NOCl2(g) 2. NOCl2(g) + NO(g) → 2NOCl(g) a. Write the overall reaction. b. Identify reaction intermediate. c. What is the molecularity of each step?

Answer»

Given :

(1) NO(g) + Cl2(g) → NOCl2(g) 

(2) NOCl2(g) + NO(g) → 2NOCl(g)

(a) Overall reaction is obtained by adding both the reactions

2NO(g) + Cl2(g) → 2NOCl2(g)

(b) The reaction intermediate is NOCl2, since it is formed in first step and consumed in the second step.

(c) Since the first step is a slow and rate determining step, the molecularity is two.

Since the second step is a fast step its molecularity is not considered.



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