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A reaction which is first order with respect to A has rate constant 6 "min"^(-1). If we start with [A] = 0.5 "mol L"^(-1), when would [A] reach the value of 0.05 ML^(-1) ? |
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Answer» SOLUTION :`k=(2.303)/t "log" ([A_0])/([A])` `k=6 "MIN"^(-1), [A]_0 =0.5, [A]=0.05`, t=? `t=(2.303)/6 "log" 0.5/0.05=2.303/6 "log"10` = 0.3838 min |
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