A reactor is supplied with 2 streams both at the rate 5 mole, one has 40% Cl2 and 60% N2, and another has pure C2H6, if the product has C2H5Cl, HCl and N2 at the rate 20 mole, what is the percentage of HCl in products?(a) 10%(b) 15%(c) 25%(d) 30%I have been asked this question in homework.This is a very interesting question from Element Material Balances in section The Chemical Reaction Equation & Stoichometry, Material Balances for Processes Involving Reaction and Multiple Units of Basic Chemical Engineering

A reactor is supplied with 2 streams both at the rate 5 mole, one has

1.	A reactor is supplied with 2 streams both at the rate 5 mole, one has 40% Cl2 and 60% N2, and another has pure C2H6, if the product has C2H5Cl, HCl and N2 at the rate 20 mole, what is the percentage of HCl in products?(a) 10%(b) 15%(c) 25%(d) 30%I have been asked this question in homework.This is a very interesting question from Element Material Balances in section The Chemical Reaction Equation & Stoichometry, Material Balances for Processes Involving Reaction and Multiple Units of Basic Chemical Engineering
Answer» Correct answer is (b) 15% For explanation: The reaction is C2H6 + Cl2 -> C2H5Cl + HCL, Let the fraction of C2H5Cl, HCl and N2 be x, y and (1 – x – y) respectively. ELEMENT balances, Cl: 0.45(2) = x10(1) + y10(1), => x + y = 0.4, C: 5(2) = x20(2), => x = 0.25, => y = 0.4 – 0.25 = 0.15, => percentage of HCl = 15%.

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