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A reacts to form P , A plot of the reciprocal of the concentration of A vs time is a straight line . When the initial concentration of A is 1.0 xx 10^(-2) M , its half-life is found to be 20 min . When initial concentration of A is 3.0 xx 10^(-3) M , the half -life will be |
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Answer» Solution :`A to P` A plot of 1/[A] vs time is a STRAIGHT line of second order . For second order , `t_(1//2) = (1)/(k[A]_(0))` where , k =rate constant `[A]_(0) ` = initial concentration of A. when , `[A]_(0) = 1 xx 10^(-2)` M , then `t_(1//2) = 20` min `20 = (1)/(k[1 xx 10^(-2)]) implies k = (1)/(20) [ 1 xx 10^(-2)] "" ... (i)` when , `[A]_(0) = 3 xx 10^(-3)` M , then `t_(1//2) = `? `t_(1//2) = (1)/(k[3 xx 10^(-3)])` substituting value of k from equation (i) `t_(1//2) = (1 xx 20 [1 xx 10^(-2)])/([3 xx 10^(-3)]) = 6.66 xx 10` min = 67 min . |
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