Saved Bookmarks
| 1. |
A rectangular coil is made of 100 turns and has dimension of 50 cm xx 20 cm, carrying a current of 10A It is placed inside a magnetic field of 5 T making an angle of 30^(@)with the field. What is the torque acting on the coil? |
|
Answer» Solution :Given, current through the coil , `I = 10 A` Area of coil , `A = 50 xx 20 = 1,000cm^(2) = 0.1 m^(2)` Angle between NORMAL to the coil and magnetic field, ` theta = 90^(@) - 30^(@) = 60^(@)` Number of turns, ` N = 100` Torque EXPERIENCED by the coil will be: ` tau = NIAB sin theta` ` = 100 xx 10 xx 0.1 xx 5 sin 60^(@)` ` = 500 xx sqrt3/2 = 433` Nm |
|