1.

A rectangular coil of area `5.0xx10^-4m^2` and `60` turns is pivoted about one of its vertical sides. The coil is in a radial horizontal magnetic field of `9xx10^-3T`. What is the torsional constant of the spring connected to the coil if a current of `0.20mA` produces an angular diflection of `18^@`?

Answer» From the equation,
`i=(k/(NAB))phi`
We find that torsional constant of the spring is given by
`k=(NABi)/phi`
Substituting the values is `SI` units we have
`k=((60)(5.0xx10^-4)(9xx10^-3)(0.2xx10^-3))/18`
`=3xx10^-9N-m//degree`


Discussion

No Comment Found

Related InterviewSolutions