Saved Bookmarks
| 1. |
A rectangular coil of N-turns, area A is held in a uniform magnetic field B. If the coil is rotated at a steady angular velocity omega, deduce an expression for the induced emf in the coil at any instant of time. |
|
Answer» SOLUTION :Consider a rectangular coil PQRS of N turns, each of area A, held in a uniform magnetic field `VECB`. Let the coil be rotated at a steady angular VELOCITY w about its own axis. Let at any instant t, normal to the area (i.e., the area vector `vecA`) subtends an angle `THETA = omega t` from direction of magnetic field `vecB`. Then, at that moment, the magnetic flux linked with the coil is ` phi_(B) = NvecB.vecA = NB Acos theta = NB Acos omegat` `THEREFORE` Induced emf `varepsilon = - (dphi_(B))dt = - d/dt (N B A cos omegat)` ` =-N B A d/dt(cos omegat) = N B A omegat` where `varepsilon_(0) = N B A omega` = maximum value of induced emf. If the coil be rotating at .f. revolutions per second, then `omega = 2pif` and the maximum induced emf `varepsilon_(0) = NBAomega = 2pifNBA`
|
|