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A rectangular coil of sides l and b carrying a current I is subjected to a uniform magnetic field vecB acting perpendicular to its plane. Obtain the expression for the torque on it. |
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Answer» Solution :We know that a rectangular coil of area A = lb , CARRYING a current I, when placed in a uniform MAGNETIC field B EXPERIENCES atorque `VEC(tau)= (I vecA) xx vecB`. As per question the magnetic field `vecB` acts perpendicular to the plane of the coil. It means that `vecB` is parallel to `vecA`. Hence Torque `|vec(tau)| = IAB sin theta = IAB sin 0^@ = 0` |
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