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A rectangular glass slab of thickness 3 cm and of refractive index 1.5 is placed in front of a concave mirror, perpendicular to its principal axis. The radius of curvature of the mirror is 10 cm. Where is an object to be placed onthe principal axis so that its image will be formed on the object? |
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Answer» SOLUTION :The rectangular GLASS slab is placed perpendicular to the principal axis of the CONCAVE mirror `M_(1)M_(2)` [Fig. 2.58]. SUPPOSE that if an OBJECT is placed at O on the principal axis, its image will be formed at O. `OABM_(1)` is the path of the ray. The ray after reflection at `M_(1)` retraces the path and forms image at O. So the ray `BM_(1)` must be incident on the mirror at `M_(1)` perpendicular. If `M_(1)B "its produced backward it intersects the principal axis at O. . So O. is the centre of curvature of the concave of the concave mirror."` `therefore "" PO. = 10cm` `Now, "" O O.= t(1-(1)/(mu)) = 3(1- (1)/(1.5))` = 3 - 2 = 1cm So, the distance of O from the concave mirror PO. + O O. = 10 + 1 = 11cm 
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