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A rectangular loop of area 0.06 m2 is placed in a magnetic field of 0.3T with its plane (i) normal to the field (ii) inclined 30^(@) to the field (iii) parallel to the field. Find the flux linked with the coil in each case. |
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Answer» Solution :`phi=NAB cos THETA` i) `phi=1 XX 0.06 xx 0.3 xx cos 0^(@)=0.018` weber ii) `phi=1 xx 0.06 xx 0.3 xx cos 60^(@)=0.009` weber III) `phi=1 xx 0.06 xx 0.3 xx cos 90^(@)=0` |
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