Saved Bookmarks
| 1. |
A rectangular loop PQMN with movable arm PQ of length 10 cm and resistance 2 Omega is placed in a uniform magnetic field of 0.1 T acting perpendicular to the plane of the loop as shown in Fig. 6.37. The resistance of the arm MN, NP and MQ are negligible. Calculate (i) the emf induced in the arm PQ, and (ii) current induced in the loop when arm PQ is moved with velocity 20 ms^(-1). |
|
Answer» Solution :Here `B = 0.1 T, l = 10 cm = 0.1 m, v = 20 ms^(-1)` and resistance `R = 2 Omega`. (i) `THEREFORE` Induced emf in the ARM `PQ, VAREPSILON = Blv = 0.1 xx 0.1 xx 20 = 0.2 V` (II)The current induced in the loop,`I = varepsilon/R=(0.2)/2= 0.1A` |
|