1.

A rectangular loop with a slide wire of length l is kept in a uniform magnetic field as shown in the figure. The resistance of slider is R. Neglecting self inductance of the loop find the current in the connector during its motion with a velocity v.

Answer»

SOLUTION : The Equivalent CIRCUIT is

The equivalent RESISTANCE of the circuit is`R = (R+ (R_1 R_2)/(R_1 + R_2) )`
Hence the current in the connector is i ` = e/R`
` THEREFORE i = (Blv (R_1 + R_2))/((R R_1 + RR_2 + R_1 + R_2))`


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