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A rectangular slab of refractive index mu is placed on another slab of refractive index 3. Both the slabs are of the same dimensions. There is a coin at the bottom of the lower slab. What should be the value of musuch that when viewed normally from above, the coin appears to be at the surface of separation of the two slabs? |
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Answer» SOLUTION :Let thickness of each SLAB be d. According to the QUESTION the apparent depth of the coin = d. `therefore "" d = (d)/(mu) + (d)/(3) or, 1= (1)/(mu) + (1)/(3)` `or, "" (1)/(mu) = (2)/(3)or, mu = (3)/(2) = 1.5` |
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