A rectangular swimming post is 40 meter long and 30 meter wide arun sw

1.	A rectangular swimming post is 40 meter long and 30 meter wide arun swim from one corner of the post to the opposite corner what distance did he swim
Answer» Question: A rectangular swimming post is 40 meter long and 30 meter wide Arun swim from ONE corner of the post to the OPPOSITE corner what distance did he swim? Given: Length of rectangular swimming post = 40 m Breadth of rectangular swimming post = 30 m To find: Distance travelled by Arun = x Displacement by Arun = y Solution: Arun started swimming from one corner and reaches the opposite corner . Let ABCD be the rectangle given in attachment. AB = DC = 40 m AD = BC = 30 m Let the Arun start from corner D and move to corner B. Then distance travelled by Arun = x x = AD + AB = 30 + 40 = 70 m. Displacement of Arun is given by diagonal of rectangle. Displacement of Arun = y $\textsf{DB=}\sqrt{(DA)^2+(AB)^2}$ $DB=\sqrt{30^2+40^2}$ $\sqrt{900+1600}$ $DB=\sqrt{2500}$ $\textsf{DB=50m}$ Answer: Displacement = y = 50m Hence the distance swum by Arun from one corner to the other corner is 50 m

A rectangular swimming post is 40 meter long and 30 meter wide arun swim from one corner of the post to the opposite corner what distance did he swim

Answer»

Question:

A rectangular swimming post is 40 meter long and 30 meter wide Arun swim from ONE corner of the post to the OPPOSITE corner what distance did he swim?

Given:

Length of rectangular swimming post = 40 m

Breadth of rectangular swimming post = 30 m

To find:

Distance travelled by Arun = x

Displacement by Arun = y

Solution:

Arun started swimming from one corner and reaches the opposite corner .

Let ABCD be the rectangle given in attachment.

AB = DC = 40 m

AD = BC = 30 m

Let the Arun start from corner D and move to corner B.

Then distance travelled by Arun = x

x = AD + AB

= 30 + 40

= 70 m.

Displacement of Arun is given by diagonal of rectangle.

Displacement of Arun = y

$\textsf{DB=}\sqrt{(DA)^2+(AB)^2}$

$DB=\sqrt{30^2+40^2}$

$\sqrt{900+1600}$

$DB=\sqrt{2500}$

$\textsf{DB=50m}$

Answer:

Displacement = y = 50m

Hence the distance swum by Arun from one corner to the other corner is 50 m