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A rectangular wire loop of sides 8 cm and 2 cm with a small cut is moving out of a region of uniform magnetic field of magnitude 0.3 T directed normal to the loop. What is the emf developed across the cut if the velocity of the loop is 1 cm s_(1) in a direction normal to the (a) longer side? (b) shorter side of the loop ? For how long does the induced voltage last in each case ? |
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Answer» Solution :Here length of loop? l = 0.08 m, breadth of loop B = 2 cm = 0.02 m, MAGNETIC field B = 0.3T, VELOCITY of the motion of loop `v = 1 cm s = 10^-2 m/s` (a) When motion is in a direction normal to the longer side, the induced emf `|varepsilon| = Blu = 0.3 xx 0.08 xx 10^(-2) = 2.4 x 10^(-4) V` and the time for which the induced voltage lasts `t = b/v=(0.02)/10^(-2)=2s` (b) When motion is in a direction normal to the shorter side, induced emf `|varepsilon| = B b v = 0.3 xx 0.02 xx 10^(5) V` amd the time for which the induced voltage lasts `t = l/v= 0.08/10^(-2) = 8s`. |
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