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A rectrangular coil 20cmxx20cm has 100 turns and carries a current of 1 A. It is placed in a uniform magnetic field B = 0.5T with the direction of magnetic field parallel to the plane of the coil. Find the magnitude of the torque required to hold this coil in this position. |
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Answer» Zero `A=20xx20xx10^(-4)m,theta=90^(@)` DEFLECTING torque `|vectau|=NIABsintheta` `|vectau|=100xx1xx400xx10^(-4)xx5xx10^(-1)xxsin90^(@)` = 2 Nm |
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