A refrigerator has to transfer an average of 263J of heat per second from temperature `-10^@C` to `25^@C`. Calculate the average power consumed, assuming no enegy losses in the process.

A refrigerator has to transfer an average of 263J of heat per second f

1.	A refrigerator has to transfer an average of 263J of heat per second from temperature `-10^@C` to `25^@C`. Calculate the average power consumed, assuming no enegy losses in the process.
Answer» Correct Answer - C Here, `T_(1)=25+273=298K` `T_(2)=-10+273=263K` `Q_2=263J//s` Coefficient of performance is given by `beta=Q_(2)/(Q_(1)-Q_(2))=T_(2)/(T_1-T_2)` `:.` (Q_1)/(Q_2)=(T_1)/(T_2)` `:.` `Q_1=T_1/T_2xxQ_2=298/263xx263` `=298Js^-1` Average power consumed, `=298-263=35Js^-1=35W`

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A refrigerator has to transfer an average of 263J of heat per second from temperature `-10^@C` to `25^@C`. Calculate the average power consumed, assuming no enegy losses in the process.

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