InterviewSolution
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InterviewSolution
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A refrigerator, whose coefficient performance `beta` is 5, extracts heat from the collingcompartment at the rate of 250 J per cycle. (a) How much work per cycle is required to operate the refrigerator? (b) How much heat per cycle is discharges the room which acts as the high temperature revervoir? |
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Answer» (a) As coefficient of performance of a refrigeration is defined as `beta=Q_(1)//W`, So `W=(Q_(1))/(beta)=(250)/(5)=50` (b) As `Q_(B)=Q_(1)+W,` so `W_(B)=250+50=300J` |
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