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A regular hexagon of side 10 cm has a charge 5 muC at each of its vertices. Calculate the potential at the centre of the hexagon. |
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Answer» Solution :Here CHARGE on each vertex of hexagon q = 5`MU C = 5 XX 10^(-6) C` SIDE of hexagon r = 10 cm=0.1 m It is clear that distance of hexagon centre O from any of the vertices of hexagon = r = 0.1 m `:.` Potential at centre of hexagon `V = 6 xx (1/(4piepsi_0).q/r)` ` = (6 xx 9 xx 10^9 xx 5 xx 10^(-6))/0.1 =2.7 xx 10^6V` |
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