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A regular hexagon of side 10cm has a charge 5muC at each of its vertices. Calculation the potential at the centre of the hexagon. |
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Answer» Solution :If .q. is the CHARGE, potential at .O. is `9 xx 10^(9) xx q/a`, where .a. is the SIDE of the exagon. TOTAL potential `=(6 xx q xx 9 xx 10^(9))/(a)` `=(9 xx 10^(9) xx 6 xx 5 xx 10^(-6))/(10 xx 10^(-2))=2.7 xx 10^(6)V or 2.7MV` 
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