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A:Relation between energy of photon (E ) and momentum (P) is P=(E )/(c ) R:Photon behaves as particle. |
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Answer» Both assertion and reason are TRUE and the reason is correct explanation of the assertion. Momentum of photon `p=(h)/(lambda)=(HF)/(c )`…..(1)`[lambda=(c )/(f)]` Photon is bundle of ENERGY which ACT as particle Energy of particle is E=nhf If n=1 and f=`(c )/(lambda)` `E=(hc)/(lambda)` ......(2) From result (1) and (2) `P=(E )/(c )` or `(hf)/(c )` |
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