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A resistance of `300Omega` and an inductance of `1/(pi)` henry are connected in series to an `AC` voltage of `20 "volts"` and `200Hz` frequency. The phase angle between the voltage and current isA. `tan^(-1) (4/3)`B. `tan^(-1) (3/4)`C. `tan^(-1) (3/2)`D. `tan^(-1) (2/5)` |
Answer» Correct Answer - A Phase angle `tan varphi=(omegaL)/R=(2pixx200)/300xx1/(pi)=4/3` `:. varphi=tan^(-1)(4/3)` |
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