1.

A resistance of 50 Omega is to be prepared using a wire of cross-sectional area 10^(-8) m^(2) and conductivity 2.2 xx 10^(6) siemens/metre. The length of the wire required is

Answer»

22.5 m
11 m
1.1 m
2.2 m.

SOLUTION :`L=(AR)/(rho)=AR SIGMA =(10^(-8))(50)(2.2xx10^(6))`


Discussion

No Comment Found

Related InterviewSolutions