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A resistor 30Omega, inductor of reactance 10Omega and capacitor of reactance 10Omega are connected in series to voltage source E = 300sqrt2 sin(omegat). Find the current in the circuit. |
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Answer» 14.14A `X_L =10 Omega` `X_C=10 Omega` `E_m =300sqrt2V` Here, `|Z|=SQRT(R^2+(X_L-X_C)^2)` `=sqrt((30)^2 +(10-10)^2)` `therefore |Z|=30Omega` `E_(rms)=E_m/sqrt2 =(300sqrt2)/2`=300 V `therefore I_(rms)=E_(rms)/"|Z|"` `=300/30` `therefore I_(rms)=10 A` |
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