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A resistor of 6kOmega with tolerance 10% and another of 4kOmega with tolerance 10% are connected in series. The tolerance of combination is about : |
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Answer» `5%` Similarly `(DeltaR_(2))/(R_(2))xx100=10` `impliesDeltaR_(2)=(4xx10)/(100)=0*4kOmega` In series, `R_(s)=R_(1)+R_(2)=6+4=10kOmega` `DeltaR_(s)=DeltaR_(1)+DeltaR_(2)=0*6+0*4` `=1kOmega` `:.(DeltaR_(s))/(R_(s))xx100=(1)/(10)xx100=10%` Hence CORRECT CHOICE is `(b)`. |
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