1.

A resistor of 6kOmega with tolerance 10% and another of 4kOmega with tolerance 10% are connected in series. The tolerance of combination is about :

Answer»

`5%`
`10%`
`12%`
`40%`

Solution :`(DeltaR_(1))/(R_(1))xx100=10impliesR_(1)=(6xx10)/(100)=0*6kOmega`
Similarly `(DeltaR_(2))/(R_(2))xx100=10`
`impliesDeltaR_(2)=(4xx10)/(100)=0*4kOmega`
In series, `R_(s)=R_(1)+R_(2)=6+4=10kOmega`
`DeltaR_(s)=DeltaR_(1)+DeltaR_(2)=0*6+0*4`
`=1kOmega`
`:.(DeltaR_(s))/(R_(s))xx100=(1)/(10)xx100=10%`
Hence CORRECT CHOICE is `(b)`.


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