1.

A resistor of 6Ω is connected in series with another resistor of 4 Ω. A potential difference of 20 V is applied across the combination. Calculate (a) the current in the circuit and (b) the potential difference across the 6Ω resistor.

Answer»

(a) R1 = 6 ohm

R2 = 4 ohm

R = R1 + R2 = 6 + 4 = 10 ohm

V = 20 V

I = V/R = 20/10 = 2 A

(b) R = 6 W

I = 2 A

V = ?

V = IR = 6 × 2 = 12 V



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