1.

The graph shown here shows the variation of terminal potential difference V, across a combination of three cells in series to a resistor, versus current i:(i) Calculate the emf of each cell.(ii) For what current i, will the power dissipation of the circuit be maximum?

Answer»

(i) Let ε be emf and r the internal resistance of each cell. The equation of terminal potential difference

V = εeff – i rint becomes

V = 3ε –i rint(i)

Where rint is effective (total) internal resistance.

From fig., when i = 0, V = 6.0 V

From (i), 6 = 3ε - 0 \(\Rightarrow \epsilon=\frac{6}{3}=2V\)

i.e., emf of each cell, ε = 2 V

Thus, emf of each cell, ε = 2V



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