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Nichrome and copper wires of same length and same radius are connected in series. Current I is passed through them. Which wire gets heated up more? Justify your answer. |
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Answer» Nichrome wire gets heated up more. Heat dissipated in a wire is given by \(H=I^2Rt\) \(H=I^2 \,\frac{pl}{A}t\) \((\because\,R=\frac{pl}{A})\) Here, radius is same, hence area (A) is same. Also, current (I) and length (l) are same. \(\therefore \,H\infty\,r\) But Pnichorme > Pcopper ∴ Hnichrome > Hcopper |
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