1.

A resistor of R = 6Omega, an inductor of L=1 H and C = 17.36 muF are connected in series with an A.C. source. Find the Q-factor.

Answer»

2.37
80
3.72
40

Solution :`Q=1/R SQRT(L/C)`
`=1/6sqrt(1/(17.36xx10^(-6)))=1/6sqrt(10^8/1736)`
`therefore Q=1/6xx10^4/41.66` = 40.006
`therefore Q approx 40`


Discussion

No Comment Found

Related InterviewSolutions